t^(1/2)-8t^(1/4)-15=0

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Solution for t^(1/2)-8t^(1/4)-15=0 equation: 


D( t )

t < 0

t < 0

t in <0:+oo)

t^(1/2)-(8*t^(1/4))-15 = 0

t^(1/2)-8*t^(1/4)-15 = 0

t_1 = t^(1/4)

1*t_1^2-8*t_1^1-15 = 0

t_1^2-8*t_1-15 = 0

DELTA = (-8)^2-(-15*1*4)

DELTA = 124

DELTA > 0

t_1 = (124^(1/2)+8)/(1*2) or t_1 = (8-124^(1/2))/(1*2)

t_1 = (2*31^(1/2)+8)/2 or t_1 = (8-2*31^(1/2))/2

t_1 = (8-2*31^(1/2))/2

t^(1/4)-((8-2*31^(1/2))/2) = 0

1*t^(1/4) = (8-2*31^(1/2))/2 // : 1

t^(1/4) = (8-2*31^(1/2))/2

( (8-2*31^(1/2))/2 < 0 i 1/4 in (0:1) ) => t naleu017Cy do O

t_1 = (2*31^(1/2)+8)/2

t^(1/4)-((2*31^(1/2)+8)/2) = 0

1*t^(1/4) = (2*31^(1/2)+8)/2 // : 1

t^(1/4) = (2*31^(1/2)+8)/2

t^(1/4) = (2*31^(1/2)+8)/2 // ^ 4

t = ((2*31^(1/2)+8)^4)/16

t = ((2*31^(1/2)+8)^4)/16

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